WebMar 31, 2024 · If in an A.P a=2 and d=3 then find s12 Advertisement Answer 12 people found it helpful misspayal66 Answer: S12 = n/2 (2a+ (12-1)d =12/6 (2*2+ (11*3) =2 (4+33) =2*37 =74 ans Find Math textbook solutions? Class 12 Class 11 Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 … WebAug 26, 2024 · If Sn denotes the sum of first n terms of an AP, then prove that S12 = 3(S8 – S4). ← Prev Question Next Question ... For a given A.P. if a = 6 and d = 3, find S4. asked Sep 1, 2024 in Arithmetic Progression by Jagat (41.4k points) arithmetic progression; class-10;
If Sn, denotes, the sum of the first n terms of an A.P. prove that S12 …
WebQuestion In an AP, given a 12=37, d =3, find a and S 12. Easy Solution Verified by Toppr a 12=37,d=3 a 12=a+(12−1)d 37=a+(11×3) 37−33=a a=4 s 12= 212[2a+(12−1)3] s 12=6[8+33] s 12=246 Was this answer helpful? 0 0 Similar questions Given a 12=37,d=3, find a and S 12 Easy View solution > In an AP : Given a 3=15, S 10=125 find d and a 10 Medium WebHot spot (as shown in Fig. 8) is then formed due to the intensified C-H 2 reaction at the initial 2–5 min. Compared to the hydrogen inlet temperature (1,123 K), the temperature rise for 1 MPa is only 40 K, suggesting the CCHG reaction occurs slowly. With increasing pressure, the maximum temperature rises for 2 MPa, 3 MPa, and 4 MPa are 110 K ... dextromethorphan hbr 15
iii In an AP: iii Given a12 = 37, d = 3, find a and S12. - BYJU
WebAnswer (1 of 8): we have to use the formula (a+(n-1)d) for ARITHMETIC PROGRESSION a is a first term in the AP n is a the term number or term location d is a common difference between successive terms in AP for the fifth term in AP TAKE a=2,d=3,n=5 a5=a+(n-1)d a5=2+(5–1)3 a5=2+(4)3 a5=14 ... WebMar 29, 2024 · Transcript. Ex 5.3, 3 In an AP (i) Given a = 5, d = 3, an = 50, find n and Sn. Given a = 5 , d = 3 , an = 50 We know that an = a + (n – 1) d Putting values 50 = 5 + (n – 1) ×3 50 = 5 + 3n – 3 50 = 2 + 3n 50 – 2 = 3n 48 = 3n 48/3=𝑛 n = 16 Now we need to find Sn Sn = 𝒏/𝟐 (𝟐𝒂+ (𝒏−𝟏)𝒅) Putting n = 16, a = 5, d = 3 ... WebOn subtracting (1) from (2), we get S8 − S4 = 8 a + 28 d − (4 a + 6 d) = 4 a + 22 d Multiplying both sides by 3, we get 3 ( S8 − S4) = 3 (4 a + 22 d) = 12 a + 66 d = S12 [From (3)] Thus, S12 = 3 ( S8 − S4 ). Concept: Sum of First n Terms of an A.P. Is … dextro curvature of spine